Question

Решить примеры ( подробно) (x+10)^2-x(x+19), если x = -99,87 (6x+5)^2-(6x-5)^2, если х = -1,5 4(2-a)^2-(2a+1)^2, если х = 0,35

Answer 1

Фоточка тебе в помощь

Answer 2

Вот я решил подробное решение ваш ответ

Answer 3

1. (x+10)^2-x(x+19), если x = -99,87

First, we need to substitute x = -99.87 into the given expression:

(x+10)^2 - x(x+19) = (-99.87 + 10)^2 - (-99.87)(-99.87 + 19)

= (-89.87)^2 - (-80.87)(-99.87)

= 8081.2969 - 8077.1179

= 4.178

Therefore, the value of the expression when x = -99.87 is 4.178.

2. (6x+5)^2-(6x-5)^2, если х = -1,5

Again, we need to substitute x = -1.5 into the given expression:

(6x+5)^2 - (6x-5)^2 = (6(-1.5) + 5)^2 - (6(-1.5) - 5)^2

= (-1)^2 - (-13)^2

= 1 - 169

= -168

Therefore, the value of the expression when x = -1.5 is -168.

3. 4(2-a)^2-(2a+1)^2, если х = 0,35

Substitute x = 0.35 into the given expression:

4(2-a)^2 - (2a+1)^2 = 4(2-0.35)^2 - (2(0.35)+1)^2

= 4(1.65)^2 - (0.7)^2

= 43.56 - 0.49

= 43.07

Therefore, the value of the expression when x = 0.35 is 43.07.