Question

(3z+1)в квадрате=9z(z+2)-2

Answer 1

9z**2+1**2=9z**2+18z-2
**2-квадрат
переносим все 
9z**2+1**2-9z**2-18z+2=0
приводим подобные и сокращаем
осталось -18z+3=0
-18z=-3
z=9

Answer 2

Держи подробное решение!!! Всего хорошего!!!!!

Answer 3

Let's begin by expanding the left-hand side of the equation using the identity:

(a+b)^2 = a^2 + 2ab + b^2

Here, a = 3z and b = 1:

(3z + 1)^2 = (3z)^2 + 2(3z)(1) + 1^2 = 9z^2 + 6z + 1

Now, we can substitute this expression back into the original equation:

(3z+1)^2 = 9z(z+2) - 2

9z^2 + 6z + 1 = 9z^2 + 18z - 2

Simplifying, we get:

6z + 1 = 18z - 2

Collecting like terms, we have:

6z - 18z = -2 - 1

-12z = -3

Solving for z, we get:

z = 1/4

Therefore, the solution to the equation is z = 1/4.