Question

(5х-7)^2=(5(х+1)^2 Срочно решите плиз

Answer 1

(5х-7)^2=(5(x+1)^2
5х^2-2*5x*(-7)+(-7)^2=5x^2-2*5x*5+5^2
-20x-7^2-5^2=0
-20x-74=0
-20x=74
x=74/-20
x= -3,7

Answer 2

Лучше решать самому, но и так хорошо)

Answer 3

To solve the equation, you can expand the squared terms and simplify:

Starting with the left-hand side of the equation:

(5x - 7)^2 = (5x - 7) × (5x - 7) = 25x^2 - 70x + 49

Next, simplify the right-hand side of the equation by expanding the square:

5(x + 1)^2 = 5(x^2 + 2x + 1) = 5x^2 + 10x + 5

Now that both sides of the equation are in terms of x^2, x, and constants, you can set them equal to each other and solve for x:

25x^2 - 70x + 49 = 5x^2 + 10x + 5

20x^2 - 80x + 44 = 0

Divide both sides by 4 to simplify:

5x^2 - 20x + 11 = 0

Using the quadratic formula:

x = [-(-20) ± sqrt((-20)^2 - 4(5)(11))] / (2(5)) x = [20 ± sqrt(20^2 - 4(5)(11))] / 10 x = [20 ± sqrt(20)] / 10 x = [20 ± 2sqrt(5)] / 10 x = 2 ± sqrt(5)/5

Therefore, the solutions for the equation are x = 2 + sqrt(5)/5 or x = 2 - sqrt(5)/5.