Question

(2х-3у)(2х+3у)+(4х+2у)(4х-2у)=

Answer 1

2х²-9у²+16х²-4у²=18у²-13х²

Answer 2

To expand this expression, we can use the FOIL (First, Outer, Inner, Last) method:

First: Multiply the first term of each binomial Outer: Multiply the outer term of each binomial Inner: Multiply the inner term of each binomial Last: Multiply the last term of each binomial

Applying the FOIL method, we get:

(2x - 3y)(2x + 3y) + (4x + 2y)(4x - 2y) = 4x^2 - 9y^2 + 12xy + 12xy + 16x^2 - 4y^2 (distributing)

Now we can combine like terms and simplify:

= 4x^2 + 16x^2 + 12xy + 12xy - 9y^2 - 4y^2 = 20x^2 + 24xy - 13y^2

Therefore, the expanded expression is 20x^2 + 24xy - 13y^2.