Question

1-cosx=? 1=sin^2x+cos^2x-cosx=sin^2x+cosx В ответах написано 2sin^2x*x/2

Answer 1

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Answer 2

To solve 1-cosx, we can use the identity:

sin^2x + cos^2x = 1

Rearranging this, we get:

sin^2x = 1 - cos^2x

Substituting this into the expression 1-cosx, we get:

1 - cosx = 1 - cosx(1)

= 1 - cos^2x/cosx

= (1 - cosx)(1 + cosx)/cosx

= sin^2x/cosx

= 2sin^2(x/2)

Therefore, 1-cosx = 2sin^2(x/2).