
Решите уравнения. 1. -6х-х^2=9 2. 2+x^2=11x 3. -9-4x^+12x=0 4. 4+9x^2=0 5. 10x+25x^2=-1 6.
x^2+2,3x=0 7. -15=-3x^2 8. -x^2=2+2x 9. 4+3x^2=-7x 10. 14-x-3x^2=0 11. x^2+25=10x 12. -8+18x-5x^2

Ответы на вопрос

В третьем не понятно..."x" в какой степени?





- -6x - x^2 = 9
Rearranging and simplifying, we get:
x^2 + 6x + 9 = 0
This is a quadratic equation in standard form. We can solve for x by factoring:
(x + 3)^2 = 0
Taking the square root of both sides, we get:
x + 3 = 0
Therefore, the solution is:
x = -3
- 2 + x^2 = 11x
Rearranging and simplifying, we get:
x^2 - 11x + 2 = 0
Using the quadratic formula:
x = (11 ± √(11^2 - 412)) / (2*1)
x = (11 ± √117) / 2
Therefore, the solutions are:
x ≈ 10.03 or x ≈ 0.97
- -9 - 4x^2 + 12x = 0
Rearranging and simplifying, we get:
4x^2 - 12x - 9 = 0
Using the quadratic formula:
x = (12 ± √(12^2 - 44(-9))) / (2*4)
x = (3 ± √21) / 2
Therefore, the solutions are:
x ≈ 2.79 or x ≈ 0.21
- 4 + 9x^2 = 0
This equation has no real solutions, since the square of any real number is non-negative.
- 10x + 25x^2 = -1
Rearranging and simplifying, we get:
25x^2 + 10x + 1 = 0
Using the quadratic formula:
x = (-10 ± √(10^2 - 4251)) / (2*25)
x = (-10 ± √-240) / 50
Since the square root of a negative number is not real, this equation has no real solutions.
- x^2 + 2.3x = 0
Factoring out x, we get:
x(x + 2.3) = 0
Therefore, the solutions are:
x = 0 or x = -2.3
- -15 = -3x^2
Dividing both sides by -3, we get:
5 = x^2
Taking the square root of both sides, we get:
x = ±√5
Therefore, the solutions are:
x ≈ 2.24 or x ≈ -2.24
- -x^2 = 2 + 2x
Rearranging and simplifying, we get:
x^2 + 2x + 2 = 0
Using the quadratic formula:
x = (-2 ± √(2^2 - 412)) / (2*1)
x = (-2 ± √-4) / 2
Since the square root of a negative number is not real, this equation has no real solutions.
- 4 + 3x^2 = -7x
Rearranging and simplifying, we get:
3x^2 + 7x + 4 = 0
Using the quadratic formula:
x = (-7 ± √(7^2 - 434)) / (2*3)
x = (-7 ± √25) / 6
Therefore, the solutions are:
x = -1 or x ≈ -1


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