Question

А) (y-3)(y+8) б) (x+4)(9+x) В) (3b-2a)(7a+b)

Answer 1

А) (y-3)(y+8)= у²+8у-3у-24=у²+5у-24.
б) (x+4)(9+x)= 9х+х²+36+4х=х²+13х+36.
В) (3b-2a)(7a+b)= 21ab+3b²-14a²-2ab=3b²-14a²+19ab.

Answer 2

а) To multiply (y-3)(y+8), you can use the FOIL method, which stands for "First, Outer, Inner, Last":

• First: multiply the first terms of each binomial, which gives y * y = y^2
• Outer: multiply the outer terms of each binomial, which gives y * 8 = 8y
• Inner: multiply the inner terms of each binomial, which gives -3 * y = -3y
• Last: multiply the last terms of each binomial, which gives -3 * 8 = -24

Putting it all together, you get: (y-3)(y+8) = y^2 + 8y - 3y - 24 = y^2 + 5y - 24

б) To multiply (x+4)(9+x), you can use the same FOIL method:

• First: multiply the first terms of each binomial, which gives x * 9 = 9x
• Outer: multiply the outer terms of each binomial, which gives x * x = x^2
• Inner: multiply the inner terms of each binomial, which gives 4 * 9 = 36
• Last: multiply the last terms of each binomial, which gives 4 * x = 4x

Putting it all together, you get: (x+4)(9+x) = x^2 + 9x + 4x + 36 = x^2 + 13x + 36

В) To multiply (3b-2a)(7a+b), you can again use the FOIL method:

• First: multiply the first terms of each binomial, which gives 3b * 7a = 21ab
• Outer: multiply the outer terms of each binomial, which gives 3b * b = 3b^2
• Inner: multiply the inner terms of each binomial, which gives -2a * 7a = -14a^2
• Last: multiply the last terms of each binomial, which gives -2a * b = -2ab

Putting it all together, you get: (3b-2a)(7a+b) = 21ab + 3b^2 - 14a^2 - 2ab = 3b^2 - 14a^2 + 19ab