Question

X*(x^2-10+25)-6*(5-x) = 0

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

X^3-10x+25x-30+6x
X^3-10x+25x+6x=30
X^3-15=30
X^3=2
X=8

Answer 3

To solve the equation $X \cdot (x^2-10+25)-6 \cdot (5-x) = 0$, we can simplify it and find the values of $x$ that satisfy the equation.

Expanding the equation, we have:

$X \cdot (x^2-10+25) - 6 \cdot (5-x) = 0$

Simplifying further:

$X \cdot (x^2+15) - 6 \cdot (5-x) = 0$

Distributing:

$X \cdot x^2 + 15X - 30 + 6x = 0$

Rearranging the terms:

$X \cdot x^2 + 6x + 15X - 30 = 0$

Now, we can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. However, I'll assume that you intended to solve for $X$ instead of $x$ because the equation doesn't have an $x$ term.

Let's assume that $x$ is a constant and solve for $X$:

$X \cdot x^2 + 15X - 30 = 0$

This is a quadratic equation in terms of $X$. To solve it, we can use the quadratic formula:

$X = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

For our equation, $a = x^2$, $b = 15$, and $c = -30$.

Plugging in these values:

$X = \frac{-15 \pm \sqrt{15^2 - 4 \cdot x^2 \cdot -30}}{2 \cdot x^2}$

Simplifying further would require knowing the specific value of $x$. If you have a specific value in mind for $x$, please let me know so I can provide a numerical solution for $X$.