Question

(b+1-2a)(a+2-b)-3a(b-1)+(a+b)^2-b(1+2a)

Answer 1

Ответ:

Объяснение:

$(b +1-2a)(a+2-b)-3a(b-1)+(a+b)^{2}-b(1+2a) = -b^{2} -2a^{2} +3ab+3b-3a-3ab+3a+a^{2}+2ab+b^{2} -b-2ab=-a^{2} +3a+2b$

Answer 2

Let's simplify the expression step by step:

Step 1: Expand the brackets: (b+1-2a)(a+2-b) = (b+1-2a)a + (b+1-2a)2 - (b+1-2a)b = ba + a + 2a - 2a^2 + 2b + 2 - ab - b - 2b + ab = 3a + 2 - 2a^2

Step 2: Simplify the terms: 3a(b-1) = 3ab - 3a (a+b)^2 = a^2 + 2ab + b^2 -b(1+2a) = -b - 2ab

Step 3: Combine like terms: 3a + 2 - 2a^2 - 3ab + 3a + a^2 + 2ab + b^2 - b - 2ab

Step 4: Rearrange the terms: -2a^2 + a^2 + 3a + 3a + 2ab - 2ab - 3ab + b^2 - b + 2

Step 5: Simplify further: -a^2 + 6a - 3ab + b^2 - b + 2

So, the simplified form of the expression (b+1-2a)(a+2-b)-3a(b-1)+(a+b)^2-b(1+2a) is -a^2 + 6a - 3ab + b^2 - b + 2.