Question

{25-6x≤4+x{3x+7,7>1+4x 1 Смотреть ответ DimasikDddd DimasikDddd ,атвылфлыдудудфдыдул

Answer 1

It seems like you have provided an inequality expression: 25-6x ≤ 4+x(3x+7) and 7 > 1+4x. Let's solve it step by step.

1. 25-6x ≤ 4+x(3x+7) To simplify the expression, let's distribute x to (3x+7): 25 - 6x ≤ 4 + 3x^2 + 7x

Rearrange the equation: 0 ≤ 3x^2 + 7x + 4 - 6x - 25 0 ≤ 3x^2 + x - 21

2. 7 > 1 + 4x Rearrange the equation: 6 > 4x x < 6/4 x < 3/2

So, we have two inequalities: 0 ≤ 3x^2 + x - 21 and x < 3/2

To solve the first inequality, we can find its roots. However, since it is a quadratic inequality, we can use a sign chart to determine the solution intervals:

x | 0 ≤ 3x^2 + x - 21

-∞ | - -7/3 | + 1 | - 7/3 | + +∞ | -

From the sign chart, we can see that the inequality is true when x is in the interval (-7/3, 1) or (7/3, +∞).

Combining the solution for the second inequality, x < 3/2, with the solution intervals for the first inequality, we have:

x < 3/2 or x ∈ (-7/3, 1) or (7/3, +∞).