Answer 1

Решаем квадратные уравнения ax² + bx + c = 0 с применением дискриминанта D = b² - 4ac         x₁₂ = (-b +-√D)/2a

x² - 14x - 32 = 0

D=14² - 4*1*(-32) = 196 + 128 = 324 = 18²

x₁₂ = (14+-18)/2 = 16 -2

x₁ = 16

x₂ = -2

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-2x² + x + 15 = 0

D = 1 - 4*(-2)*15 = 1 + 120 = 121 = 11²

x₁₂ = (-1 +- 11)/2*(-2) = ( -1 +- 11)/(-4) = 3  -5/2

x₁ = 3

x₂ = -5/2

Answer 2

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