Question

1) (a^2+b^2)^3=? 2) (2a^2-3b^2)^3=? 3) (7m^3+9n^4)^3=? 4) (0.3x^5+0.5y^2)^3=? 5) (1.5a^3+0.3b^4)^3=?

Answer 1

А что именно нужно сделать? Разложить на множители? 
1) ( a^2+b^2)^3=b^6+3*a^2*b^4+3*a^4*b^2+a^6
2) (2a^2- 3*b^2)^3=8*a^6+54*a^2*b^4-36*a^4*b^2-27*b^6
3) (7m^3+9n^4)^3=729*n^12+1701*m^3*n^8+1323*m^6*n^4+343*m^9
4) (0.3x^5+0.5y^2)^3=0.001*(125*y^6+225*x^5*y^4+135*x^10*y^2+27*x^15)
5)  (1.5a^3+0.3b^4)^3=0.001*(27*b^12+405*a^3*b^8+2025*a^6*b^4+3375*a^9)
По идее так) 

Answer 2

Let's calculate the expressions you provided:

1. (a^2 + b^2)^3

Expanding the expression: (a^2 + b^2)^3 = (a^2 + b^2)(a^2 + b^2)(a^2 + b^2)

Using the binomial expansion formula, we get: (a^2 + b^2)^3 = a^6 + 3a^4b^2 + 3a^2b^4 + b^6

2. (2a^2 - 3b^2)^3

Expanding the expression: (2a^2 - 3b^2)^3 = (2a^2 - 3b^2)(2a^2 - 3b^2)(2a^2 - 3b^2)

Using the binomial expansion formula, we get: (2a^2 - 3b^2)^3 = 8a^6 - 36a^4b^2 + 54a^2b^4 - 27b^6

3. (7m^3 + 9n^4)^3

Expanding the expression: (7m^3 + 9n^4)^3 = (7m^3 + 9n^4)(7m^3 + 9n^4)(7m^3 + 9n^4)

Using the binomial expansion formula, we get: (7m^3 + 9n^4)^3 = 343m^9 + 1323m^6n^4 + 1701m^3n^8 + 729n^12

4. (0.3x^5 + 0.5y^2)^3

Expanding the expression: (0.3x^5 + 0.5y^2)^3 = (0.3x^5 + 0.5y^2)(0.3x^5 + 0.5y^2)(0.3x^5 + 0.5y^2)

Using the binomial expansion formula, we get: (0.3x^5 + 0.5y^2)^3 = 0.027x^15 + 0.135x^10y^2 + 0.225x^5y^4 + 0.125y^6

5. (1.5a^3 + 0.3b^4)^3

Expanding the expression: (1.5a^3 + 0.3b^4)^3 = (1.5a^3 + 0.3b^4)(1.5a^3 + 0.3b^4)(1.5a^3 + 0.3b^4)

Using the binomial expansion formula, we get: (1.5a^3 + 0.3b^4)^3 = 3.375a^9 + 2.7a^6b^4 + 0.81a^3b^8 + 0.216b^12

These are the expanded forms of the given expressions raised to the power of 3.