Question

Y*2-11y+30=0 please can you decide this number?

Answer 1

y^2-11y+30=0

D=b^2-4ac=(-11)^2 - 4*1*30=121-120=1

VD=V1=1

y1=(11+1)/2=12/2=6

y2=(11-1)/2=10/2=5

 

 

 

Answer 2

To solve the quadratic equation Y^2 - 11Y + 30 = 0, we can use the quadratic formula:

Y = (-b ± √(b^2 - 4ac)) / (2a)

For the given equation, a = 1, b = -11, and c = 30. Plugging in these values, we have:

Y = (11 ± √((-11)^2 - 4(1)(30))) / (2(1)) Y = (11 ± √(121 - 120)) / 2 Y = (11 ± √1) / 2

Now we can simplify further:

Y = (11 + 1) / 2 = 12 / 2 = 6 Y = (11 - 1) / 2 = 10 / 2 = 5

Therefore, the solutions to the quadratic equation Y^2 - 11Y + 30 = 0 are Y = 6 and Y = 5.