Question

(х-3)в квадрате -2(х-3)-15=0

Answer 1

(x-3)^2-2(x-2)-15=0
x^2-6x+9-2x+6-15=0
x^2-8x=0
x(x-8)=0
x1=0    x-8=0
            x2=8
Ответ x=0. x=8

Answer 2

To solve the quadratic equation $(x-3)^2 - 2(x-3) - 15 = 0$, we can use the quadratic formula or simplify the equation and solve it by factoring. Let's go with the factoring method.

Let's start by expanding the squared term $(x-3)^2$: $(x-3)(x-3) - 2(x-3) - 15 = 0$

Expanding, we have: $(x^2 - 6x + 9) - 2(x-3) - 15 = 0$

Distribute -2: $x^2 - 6x + 9 - 2x + 6 - 15 = 0$

Combine like terms: $x^2 - 8x = 0$

Now, let's factor out an $x$: $x(x - 8) = 0$

To find the solutions, we set each factor equal to zero and solve for $x$: $x = 0$ or $x - 8 = 0$

For $x - 8 = 0$, adding 8 to both sides gives: $x = 8$

Therefore, the solutions to the quadratic equation are $x = 0$ and $x = 8$.