Question

​

Answer 1

$2sin^22x-1=0\\\\sin^22x=\frac{1}{2}\; \; ,\qquad \Big [\; sin^2a=\frac{1-cos2a}{2}\; \Big ]\\\\\frac{1-cos4x}{2}=\frac{1}{2}\\\\1-cos4x=1\\\\cos4x=0\\\\4x=\frac{\pi }{2}+\pi n\; ,\; n\in Z\\\\x=\frac{\pi }{8}+\frac{\pi n}{4}\; ,\; n\in Z$

Answer 2

Hello! How can I assist you today?