Question

-3x^2+2x+6=-x^2+3x-(-3+2x^2)​

Answer 1

Здесь подробно расписано решение

Answer 2

To solve the equation, let's simplify and combine like terms on both sides:

-3x^2 + 2x + 6 = -x^2 + 3x - (-3 + 2x^2)

First, simplify the right side by distributing the negative sign to each term within the parentheses:

-3x^2 + 2x + 6 = -x^2 + 3x - (-3) + (-2x^2)

Simplify further by removing the parentheses:

-3x^2 + 2x + 6 = -x^2 + 3x + 3 + (-2x^2)

Combine like terms:

-3x^2 + 2x + 6 = -3x^2 + 3x + 3 - 2x^2

Now, let's simplify and combine the x^2 terms and the x terms:

(-3x^2 + 3x^2) + (2x - 3x) + 6 = 3 + 3

0x^2 - x + 6 = 6

Simplifying further:

-x + 6 = 6

Now, let's isolate the x term. Subtract 6 from both sides:

-x + 6 - 6 = 6 - 6

-x = 0

To solve for x, multiply both sides by -1 (to get rid of the negative sign in front of x):

-1 * (-x) = 0 * (-1)

x = 0

Therefore, the solution to the equation -3x^2 + 2x + 6 = -x^2 + 3x - (-3 + 2x^2) is x = 0.