Question

1. 5^x-6=1 2. 3^x+2+3^x=30

Answer 1

эмммм, да я хз если честно

Answer 2

Let's solve the given equations step by step:

1. 5^x - 6 = 1

Adding 6 to both sides of the equation, we have:

5^x = 1 + 6 5^x = 7

Taking the logarithm (base 5) of both sides:

x = log₅(7)

Using logarithmic properties, we can convert this equation to base 10 logarithm:

x = log₅(7) / log₅(10)

Using the change of base formula for logarithms, we can rewrite it as:

x = log₁₀(7) / log₁₀(5)

Using a calculator, you can approximate the value of x.

2. 3^x + 2 + 3^x = 30

Combining like terms, we get:

2 * 3^x + 2 = 30

Subtracting 2 from both sides:

2 * 3^x = 30 - 2 2 * 3^x = 28

Dividing both sides by 2:

3^x = 28 / 2 3^x = 14

Taking the logarithm (base 3) of both sides:

x = log₃(14)

Using logarithmic properties, we can convert this equation to base 10 logarithm:

x = log₃(14) / log₃(10)

Using the change of base formula for logarithms, we can rewrite it as:

x = log₁₀(14) / log₁₀(3)

Using a calculator, you can approximate the value of x.