Question

№3 3^ -8 степени умноженное(3 ^5 степени)² 5^-7 умноженное (5^5)² (√40 + 4) ² №4 -4/3х²+ 12=0 -1/3х²+27=0

Answer 1

Сейчас посмотрю. Мы кажется делали похожее

Answer 2

3^-8 степени умноженное (3^5)^2=3^-8 степени умноженное 3^10 степени=3^2 степени
5^-7 степени умноженное (5^5)^2=5^-7 степени умноженное 5^10 степени=5^3 степени

Answer 3

№3: To simplify the expression, let's break it down step by step:

3^(-8) multiplied by (3^5)^2 multiplied by 5^(-7) multiplied by (5^5)^2 multiplied by (√40 + 4)^2

First, let's simplify the exponents:

3^(-8) = 1/3^8

(3^5)^2 = 3^10

5^(-7) = 1/5^7

(5^5)^2 = 5^10

Now we can rewrite the expression:

(1/3^8) * (3^10) * (1/5^7) * (5^10) * (√40 + 4)^2

Next, let's simplify the square root and the addition:

√40 = √(4 * 10) = 2√10

Now the expression becomes:

(1/3^8) * (3^10) * (1/5^7) * (5^10) * (2√10 + 4)^2

Let's simplify further:

(1/6561) * (59049) * (1/78125) * (9765625) * (2√10 + 4)^2

Now we can simplify the fractions and the squares:

(59049/510183135625) * (9765625/6561) * (2√10 + 4)^2

Finally, we can simplify the expression:

(23597844140625/33650980812890625) * (2√10 + 4)^2

Simplification may be possible further, depending on the specific requirements of the problem or context in which the expression is used.

№4: We have two equations:

1. -4/3x^2 + 12 = 0
2. -1/3x^2 + 27 = 0

To solve equation 1:

-4/3x^2 + 12 = 0

Multiply both sides by 3 to eliminate the fraction:

-4x^2 + 36 = 0

Subtract 36 from both sides:

-4x^2 = -36

Divide by -4:

x^2 = 9

Take the square root of both sides:

x = ±√9

x = ±3

So, for equation 1, x can be either 3 or -3.

To solve equation 2:

-1/3x^2 + 27 = 0

Multiply both sides by 3 to eliminate the fraction:

-x^2 + 81 = 0

Subtract 81 from both sides:

-x^2 = -81

Divide by -1:

x^2 = 81

Take the square root of both sides:

x = ±√81

x = ±9

So, for equation 2, x can be either 9 or -9.