Question

6) 2 – 0,7х2 + 3x = x + 2.од,​

Answer 1

Ответ:

Объяснение:

$\[\begin{gathered}2-0,7{x^2}+3x=x+2\hfill\\2-0.7{x^2}+3x-x-2=0\hfill\\2x-0.7{x^2}=0\hfill\\x(2-0.7x)=0\hfill\\\boxed{{x_1}=0}\;\;\;\;\;\;\;\;(2-0.7x)=0\hfill\\\hspace{60pt}-0.7x=-2\hfill\\\hspace{60pt}x=-2:(-0.7)\hfill\\\hspace{60pt}\boxed{{x_2}=2\frac{6}{7}}\hfill\\\end{gathered}\]$

Answer 2

To solve the equation 2 - 0.7x^2 + 3x = x + 2, you can follow these steps:

1. Start by combining like terms on both sides of the equation. 2 - 0.7x^2 + 3x = x + 2 Rearrange the terms to group the x-terms together: -0.7x^2 + 3x - x = 2 - 2

2. Simplify the equation further: -0.7x^2 + 2x = 0

3. To solve the quadratic equation, set it equal to zero by moving all the terms to one side: -0.7x^2 + 2x = 0

4. Factor out the common factor, if possible. In this case, x can be factored out: x(-0.7x + 2) = 0

5. Now, set each factor equal to zero and solve for x: x = 0 (from the factor x = 0) -0.7x + 2 = 0 (from the factor -0.7x + 2 = 0)

   Solve the second equation: -0.7x = -2 Divide both sides by -0.7: x = -2 / -0.7 x ≈ 2.857

So, the solutions to the equation are x = 0 and x ≈ 2.857.