Question

(b-1 cтепени+а-1степени)*(a+b)-1степени

Answer 1

$(b^{-1}+a^{-1})(a+b)^{-1}=(\frac{1}{b}+\frac{1}{a})\cdot \frac{1}{a+b}=\\=\frac{a+b}{ab}\cdot \frac{1}{a+b}=\frac{1}{ab}$

Answer 2

To simplify the expression you provided, let's break it down step by step:

The expression is:

(b^(-1) + a^(-1)) * (a + b)^(-1)

Step 1: Simplify the exponents:

Recall that the exponent of -1 means the reciprocal of the term. Therefore, b^(-1) is equal to 1/b, and a^(-1) is equal to 1/a.

So now we have:

(1/b + 1/a) * (a + b)^(-1)

Step 2: Combine the fractions:

To combine the fractions, we need to find a common denominator, which in this case is ab.

So the expression becomes:

((a + b) / (ab)) * (a + b)^(-1)

Step 3: Simplify further:

Multiplying a fraction by its reciprocal gives us 1. Therefore, (a + b) / (ab) * (a + b)^(-1) simplifies to just 1.

So the final simplified expression is:

1