Question

(РИСУНОК)Вертолет поднялся на высоту 800м за 3мин 20сек.при этом был отнесен ветром в горизонтальном положении на 600м.Определите перемещение и скорость вертолета относительно взлетной площадке

Answer 1

Problem Analysis

To determine the displacement and velocity of the helicopter relative to the takeoff pad, we need to consider both the vertical and horizontal components of its motion. The given information includes the height the helicopter reached, the time it took, and the horizontal displacement caused by the wind. We can use this information to calculate the displacement and velocity.

Calculation of Displacement

The displacement of the helicopter can be calculated by considering the vertical and horizontal components separately.

1. Vertical Displacement: - The helicopter climbed to a height of 800 meters. - Therefore, the vertical displacement is 800 meters.

2. Horizontal Displacement: - The wind caused the helicopter to be displaced horizontally by 600 meters. - Therefore, the horizontal displacement is 600 meters.

3. Total Displacement: - The total displacement can be calculated using the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. - In this case, the vertical displacement is one side of the right triangle, and the horizontal displacement is the other side. - Using the Pythagorean theorem, we can calculate the total displacement as follows: - Total Displacement = √(Vertical Displacement^2 + Horizontal Displacement^2) - Total Displacement = √(800^2 + 600^2) - Total Displacement ≈ 1000 meters

Therefore, the displacement of the helicopter relative to the takeoff pad is approximately 1000 meters.

Calculation of Velocity

The velocity of the helicopter can be calculated by dividing the displacement by the time taken.

1. Time Taken: - The helicopter took 3 minutes and 20 seconds to reach the height of 800 meters. - Converting the time to seconds: 3 minutes × 60 seconds/minute + 20 seconds = 200 seconds.

2. Velocity: - Velocity = Displacement / Time Taken - Velocity = 1000 meters / 200 seconds - Velocity = 5 meters/second

Therefore, the velocity of the helicopter relative to the takeoff pad is 5 meters/second.

Conclusion

The displacement of the helicopter relative to the takeoff pad is approximately 1000 meters, and its velocity is 5 meters/second.