Question

Пожалуйста сделайте физику : 1 вычислить давление жидкости плотностью 1800кг/м в кубе на дно цилиндрического сосуда если высота ее столба равна 10 см 2 в сосуде находится один над другим три слоя несмешивающихся жидкостей воды масла и ртути. высота каждого слоя- 5 см Определите давление на дно сосуда и на глубине 8 см.3 плоскодонная баржа получила пробоину в Дне площадью сечения 200 см в квадрате. С какой силой нужно давить на пластырь запятая которым закрывают отверстие, чтобы сдержать напор воды на глубине 2 метра?

Answer 1

Calculation of Pressure in a Liquid

To calculate the pressure at the bottom of a cylindrical vessel filled with a liquid, we can use the formula:

Pressure = Density x Gravity x Height

Given: - Density of the liquid = 1800 kg/m³ - Height of the liquid column = 10 cm = 0.1 m

Using the given values, we can calculate the pressure at the bottom of the vessel:

Pressure = 1800 kg/m³ x 9.8 m/s² x 0.1 m = 1764 Pa [[1]].

Therefore, the pressure at the bottom of the cylindrical vessel is 1764 Pascal.

Pressure at a Depth of 8 cm

To calculate the pressure at a depth of 8 cm, we need to consider the pressure due to the weight of the liquid column above that depth.

Given: - Height of each liquid layer = 5 cm = 0.05 m

To calculate the pressure at a depth of 8 cm, we need to consider the pressure due to the weight of the water column (density = 1000 kg/m³) and the oil column (density = ρ) above that depth.

The pressure at a depth of 8 cm can be calculated as follows:

Pressure = Pressure due to water column + Pressure due to oil column

Pressure due to water column = Density of water x Gravity x Height of water column

Pressure due to oil column = Density of oil x Gravity x Height of oil column

Given: - Density of water = 1000 kg/m³ - Density of oil = ρ (unknown) - Height of water column = 8 cm = 0.08 m - Height of oil column = 5 cm = 0.05 m

Using the given values, we can calculate the pressure at a depth of 8 cm:

Pressure due to water column = 1000 kg/m³ x 9.8 m/s² x 0.08 m = 784 Pa [[2]].

To calculate the pressure due to the oil column, we need to know the density of the oil. Unfortunately, the density of the oil is not provided in the question. Therefore, we cannot calculate the pressure at a depth of 8 cm without knowing the density of the oil.

Force Required to Hold Back Water Pressure

To calculate the force required to hold back the water pressure, we can use the formula:

Force = Pressure x Area

Given: - Area of the hole in the bottom of the barge = 200 cm² = 0.02 m² - Depth of water = 2 meters

To calculate the force required to hold back the water pressure at a depth of 2 meters, we need to consider the pressure due to the weight of the water column above that depth.

Pressure = Density x Gravity x Depth

Given: - Density of water = 1000 kg/m³ - Depth of water = 2 m

Using the given values, we can calculate the pressure at a depth of 2 meters:

Pressure = 1000 kg/m³ x 9.8 m/s² x 2 m = 19600 Pa [[3]].

Now, we can calculate the force required to hold back the water pressure:

Force = Pressure x Area = 19600 Pa x 0.02 m² = 392 N.

Therefore, the force