Question

Масса оболочки воздушного шара составляет 310 кг. Надутый гелием он может поднять груз массой 1500 кг. При этом плотность гелия в шаре 0,18 кг/м3, а плотность воздуха 1,29 кг/м3. Чему равен объем воздушного шара? ПОМОГИТЕ, ПОЖАЛУЙСТА!

Answer 1

Fa=Fт
Fт= gpгелияV+mg(вес оболочки)+m1g(груз)
Fa=gpвоздухаV
gpгелияV+mg+m1g=gpвоздухаV
gpвоздухаV-gpгелияV=mg+m1g
Vg(pвоздуха-pгелия)=mg+m1g
V(pвоздуха-pгелия)=m+m1
V=(m+m1)/(pвоздуха-pгелия)=(1500+310)/1.29-0.18=1630.63

Answer 2

Calculation of the Volume of the Airship

To calculate the volume of the airship, we can use the given information about the mass of the envelope, the lifting capacity of helium, and the densities of helium and air.

Let's denote the volume of the airship as V (in cubic meters).

The mass of the envelope is given as 310 kg.

The lifting capacity of helium is given as 1500 kg.

The density of helium in the airship is given as 0.18 kg/m^3.

The density of air is given as 1.29 kg/m^3.

To calculate the volume of the airship, we can use the following equation:

V * (density of air - density of helium) = mass of the envelope + lifting capacity of helium

Substituting the given values into the equation, we have:

V * (1.29 kg/m^3 - 0.18 kg/m^3) = 310 kg + 1500 kg

Simplifying the equation, we get:

V * 1.11 kg/m^3 = 1810 kg

Dividing both sides of the equation by 1.11 kg/m^3, we find:

V = 1810 kg / 1.11 kg/m^3

Calculating the value, we have:

V ≈ 1632.43 m^3

Therefore, the volume of the airship is approximately 1632.43 cubic meters.

Please note that this calculation assumes ideal conditions and does not take into account factors such as the weight of the payload or the shape of the airship.