Question

Какое давление на стенки сосуда производит газ, если его масса 3×10^-3 кг, объем 0,5 л, а средняя скорость движения молекул 500 м/с? Ответ запишите в кПа.

Answer 1

Из основного уравнения МКТ ..

n=N\V

p=$\frac{m_{0} N}{3v}$*v^2

p=$\frac{m}{3v}$*v^2

p=$\frac{3*10^-3}{3*0,5*10^-3} *500^{2} =500000=500$кПа

Ответ:500кПа

Answer 2

Calculation of Pressure

To calculate the pressure exerted by the gas on the walls of the vessel, we can use the formula:

Pressure = (mass of gas * average velocity^2) / (volume of the vessel)

Given: - Mass of the gas = 3×10^-3 kg - Volume of the vessel = 0.5 L = 0.5 * 10^-3 m^3 - Average velocity of the gas molecules = 500 m/s

Using the given values in the formula, we can calculate the pressure:

Pressure = (3×10^-3 kg * (500 m/s)^2) / (0.5 * 10^-3 m^3)

Calculating this expression gives us the pressure exerted by the gas on the walls of the vessel.

Please note that the given sources do not provide direct information related to this specific calculation. Therefore, the calculation is based on the general principles of gas pressure and kinetic theory of gases.

Let's calculate the pressure: