Question

17. Груз массой 100 г совершает колебания на пружине жесткостью 40 Н/м. Чему равно наибольшее значение модуля скорости тела, если амплитуда колебаний 9 см? Помогите пожалуйста!

Answer 1

Вот не за что)))))))))))

Answer 2

Calculation of the Maximum Value of the Body's Speed Module

To calculate the maximum value of the body's speed module during its oscillations on a spring, we can use the formula:

v_max = A * ω

Where: - v_max is the maximum value of the body's speed module, - A is the amplitude of the oscillations, - ω is the angular frequency of the oscillations.

In this case, the mass of the body is 100 g and it is undergoing oscillations on a spring with a stiffness of 40 N/m. The amplitude of the oscillations is given as 9 cm.

To find the angular frequency, we can use the formula:

ω = √(k / m)

Where: - k is the stiffness of the spring, - m is the mass of the body.

Let's calculate the angular frequency first:

ω = √(40 N/m / 0.1 kg)

ω = √(400 N/kg)

ω = 20 rad/s

Now, we can calculate the maximum value of the body's speed module:

v_max = 0.09 m * 20 rad/s

v_max = 1.8 m/s

Therefore, the maximum value of the body's speed module is 1.8 m/s.