Question

Найдите амплитуду ЭДС, наводимой в рамке, вращающейся в однородном магнитном поле, если частота вращения составляет 30 об/с, площадь рамки 120 см и магнитная индукция 0,4 Тл

Answer 1

Em=B*S*w=B*S*2*pi*n=0,4*120*10^-4*6,28*30=0,9 B

Answer 2

дано v=30 об\с  s=120см2   B=0,4Тл    Ем- ?

Ем=B*S*w=B*S*2*п*v=0,4*0,012*6,28*30=0.9В

Answer 3

Calculation of the EMF Amplitude in a Rotating Frame

To calculate the amplitude of the electromotive force (EMF) induced in a rotating frame in a uniform magnetic field, we can use the formula:

E = B * A * ω

Where: - E is the amplitude of the EMF - B is the magnetic induction (also known as magnetic field strength) - A is the area of the frame - ω is the angular velocity of rotation

Given the following values: - Angular velocity (ω) = 30 revolutions per second - Area of the frame (A) = 120 cm² - Magnetic induction (B) = 0.4 T (Tesla)

Let's substitute these values into the formula to calculate the amplitude of the EMF.

E = 0.4 T * 120 cm² * 30 rev/s

To proceed with the calculation, we need to convert the area from cm² to m² and the angular velocity from rev/s to rad/s.

1 cm² = 0.0001 m² 1 revolution = 2π radians

Converting the area: 120 cm² * 0.0001 m²/cm² = 0.012 m²

Converting the angular velocity: 30 rev/s * 2π rad/rev = 60π rad/s

Now we can substitute the converted values into the formula:

E = 0.4 T * 0.012 m² * 60π rad/s

Simplifying the expression: E = 0.288π T·m²/s

Therefore, the amplitude of the EMF induced in the rotating frame is approximately 0.288π T·m²/s.

Please note that the value of π (pi) is an irrational number approximately equal to 3.14159.