Question

Поезд идёт со скоростью 20 м\с . чему будет равна скорость поезда после торможения , происходящего с ускорением 0, 25м\с в квадрате в течении 20с?

Answer 1

V=vo+at=20+0,25*20=25 м/с

Answer 2

Calculation of the Final Velocity of the Train

To calculate the final velocity of the train after braking, we can use the equation of motion:

v = u + at

Where: - v is the final velocity of the train - u is the initial velocity of the train - a is the acceleration (negative in this case, as it represents deceleration due to braking) - t is the time taken for braking

Given: - Initial velocity (u) = 20 m/s - Acceleration (a) = -0.25 m/s^2 (negative because it represents deceleration) - Time taken for braking (t) = 20 s

Substituting these values into the equation, we can calculate the final velocity (v):

v = 20 + (-0.25) * 20

Calculating the above expression:

v = 20 - 5

Therefore, the final velocity of the train after braking for 20 seconds with an acceleration of -0.25 m/s^2 will be 15 m/s.