Question

Человек прошел по аллее парка 40м. Затем он повернул на вторую аллею, расположенную под углом 90° к первой аллее и прошел по ней еще 30м.Определите пройденный путь и модуль перемещения человека.

Answer 1

Движение будет выглядеть как прямоугольный треугольник, где нам известны 2 катета. Перемещение будет здесь гипотенузой. 


Sперемещения = 50

Answer 2

Calculation of the Distance Traveled and Displacement

To calculate the distance traveled and displacement of the person, we can use the given information:

- The person walked 40 meters along the first alley. - Then, the person turned onto the second alley, which is at a 90° angle to the first alley, and walked an additional 30 meters.

To find the distance traveled, we can add the lengths of both alleys: 40 meters + 30 meters = 70 meters.

To find the displacement, we need to consider the straight-line distance from the starting point to the ending point. Since the person turned at a 90° angle, the displacement is the hypotenuse of a right triangle formed by the two alleys.

Using the Pythagorean theorem, we can calculate the displacement as follows:

Displacement = √(40^2 + 30^2) = √(1600 + 900) = √2500 = 50 meters.

Therefore, the person traveled a distance of 70 meters and had a displacement of 50 meters.