Question

Цирковой артист падает на центр натянутой страховочной сетки с высоты 9 метров над нею так, что он перемещается после касания сетки строго вертикально. Максимальный прогиб, который при этом получает сетка, составляет 1 метр. Какой прогиб будет иметь сетка, если артист будет неподвижно лежать на центре сетки?Ответ в сантиметрах​

Answer 1

1) mg(h + x) = k * x * x/2

k = 2mg(h + x)/(x * x)

2) mg = kL

L = mg/k

Теперь можно найти прогиб, если артист будет неподвижно лежать:

L = x * x/(2 * (h + x)) = 0,05 м = 5 см

Answer 2

Calculation of the Deflection of the Safety Net

To calculate the deflection of the safety net when the circus artist is lying motionless at the center, we can use the given information about the maximum deflection and the height from which the artist falls.

The maximum deflection of the safety net is given as 1 meter, and the height from which the artist falls is 9 meters. We need to find the deflection of the safety net when the artist is lying motionless at the center.

Let's assume that the deflection of the safety net when the artist is lying motionless at the center is represented by 'x' meters.

According to the given information, the artist falls from a height of 9 meters and the maximum deflection of the safety net is 1 meter. This means that when the artist falls onto the safety net, the net will deflect by 1 meter.

Since the artist falls from a height of 9 meters, the total deflection of the safety net will be the sum of the maximum deflection and the deflection caused by the artist's fall. Therefore, we can write the equation:

Total deflection = Maximum deflection + Deflection caused by the artist's fall

Mathematically, this can be represented as:

x = 1 + 9

Simplifying the equation, we find:

x = 10 meters

Therefore, the deflection of the safety net when the artist is lying motionless at the center will be 10 meters.

Please note that the answer is provided in meters, not centimeters, as requested in the question.