Question

тело соверщает гармонические колебания с циклической частотой 10 с^-1 если тело при прохождении им положения равесия имеет скорость 0,2 м/с то амплитуда колебаний равна

Answer 1

Дано:

V=0.2м

ω=10`-1=0.1рад\с

Xm-?

V=Xm*ω

Xm=V \ω=0.2\0.1=2

Отает 2

Answer 2

Calculation of Amplitude of Harmonic Oscillation

To calculate the amplitude of a harmonic oscillation, we need to know the cyclic frequency (ω) and the velocity (v) of the object when it passes through its equilibrium position.

Given: - Cyclic frequency (ω) = 10 s^-1 - Velocity (v) = 0.2 m/s

The amplitude (A) of the oscillation can be calculated using the formula:

A = v / ω

Substituting the given values into the formula, we get:

A = 0.2 m/s / 10 s^-1

Simplifying the expression, we find:

A = 0.02 m

Therefore, the amplitude of the oscillation is 0.02 meters.