Question

Ответы:Самолет массой 100 т взлететь на высоту 1 км со скоростью 200м/ с какова его механическая энергия относительно земли/

Answer 1

Е=К+П

К=mv(квадрат)/2=2000000000Дж

П=мqh=1000000000Дж

Е=3000МДж 

Answer 2

Calculation of Mechanical Energy

To calculate the mechanical energy of an airplane with a mass of 100 tons (100,000 kg) that takes off to a height of 1 km with a speed of 200 m/s, we can use the formula for mechanical energy:

Mechanical Energy (E) = Kinetic Energy (KE) + Potential Energy (PE)

The kinetic energy of an object is given by the formula:

KE = (1/2) * mass * velocity^2 The potential energy of an object at a certain height is given by the formula:

PE = mass * gravity * height where gravity is the acceleration due to gravity (approximately 9.8 m/s^2).

Let's calculate the kinetic energy and potential energy separately and then add them to find the total mechanical energy.

1. Calculation of Kinetic Energy (KE):

Using the formula for kinetic energy:

KE = (1/2) * mass * velocity^2

Substituting the given values:

KE = (1/2) * 100,000 kg * (200 m/s)^2

Calculating:

KE = 1/2 * 100,000 kg * 40,000 m^2/s^2

KE = 2,000,000,000 J

2. Calculation of Potential Energy (PE):

Using the formula for potential energy:

PE = mass * gravity * height

Substituting the given values:

PE = 100,000 kg * 9.8 m/s^2 * 1,000 m

Calculating:

PE = 980,000,000 J

3. Calculation of Mechanical Energy (E):

Adding the kinetic energy and potential energy:

E = KE + PE

E = 2,000,000,000 J + 980,000,000 J

Calculating:

E = 2,980,000,000 J

Therefore, the mechanical energy of the airplane relative to the ground is 2,980,000,000 Joules.

Please note that the above calculations assume ideal conditions and do not take into account factors such as air resistance or energy losses due to friction.