Question

Два конденсатора ёмкости которых 2,5 и 5,0 мкФ соединены последовательно и подключены к источнику постоянного напряжения 250В. Определить общую электроёмкость и напряжение на кождом конденсаторе

Answer 1

1/C =1/C1 +1/C2 = 1/2,5 +1/5 = 3/5 ; C = 5/3 мкФ = 1,67 мкФ
q1=q2 =q = UC = 250*5/3*10^-6 =  1250/3*10^-6 Кл 
U1 = q1/C1 = 1250/3*10^-6 / 2,5*10^-6 = 500/3 = 166,67 B
U2 = q2/C2 = 1250/3*10^-6 / 5*10^-6 = 250/3 = 83,33 B

Answer 2

Calculation of Total Capacitance and Voltage across Each Capacitor

To determine the total capacitance and voltage across each capacitor, we can use the formula for capacitors connected in series. In a series connection, the total capacitance is given by the reciprocal of the sum of the reciprocals of the individual capacitances. The voltage across each capacitor is the same and equal to the applied voltage.

Let's calculate the total capacitance and voltage across each capacitor using the given values:

Given: - Capacitance of the first capacitor (C1): 2.5 μF - Capacitance of the second capacitor (C2): 5.0 μF - Applied voltage (V): 250 V

Total Capacitance (C_total): The total capacitance (C_total) can be calculated using the formula:

1 / C_total = 1 / C1 + 1 / C2

Substituting the given values:

1 / C_total = 1 / 2.5 + 1 / 5.0

Simplifying the equation:

1 / C_total = 0.4 + 0.2
1 / C_total = 0.6

Taking the reciprocal of both sides:

C_total = 1 / (1 / C_total)
C_total = 1 / 0.6
C_total = 1.67 μF

Therefore, the total capacitance (C_total) is 1.67 μF.

Voltage across each capacitor: The voltage across each capacitor is equal to the applied voltage (V). In this case, the voltage across each capacitor is 250 V.

To summarize: - The total capacitance (C_total) is 1.67 μF. - The voltage across each capacitor is 250 V.

Please let me know if there is anything else I can help you with!