Question

К пружине подвесили груз 20кг. На сколько растянулась пружина, если ее жесткость 40н\м? Ускорение свободного падения взять за 10м\с в квадрате.

Answer 1

Я написала печатными, хоть их попробуй разобрать. просто я на врача учусь :)

Answer 2

Calculation of the Spring Extension

To calculate the extension of the spring when a 20 kg weight is suspended from it, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the extension or compression of the spring.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force applied to the spring (in newtons) - k is the spring constant or stiffness (in newtons per meter) - x is the extension or compression of the spring (in meters)

In this case, the weight of the object is acting as the force applied to the spring. The weight can be calculated using the formula:

Weight = mass * acceleration due to gravity

Given that the mass is 20 kg and the acceleration due to gravity is 10 m/s², we can calculate the weight:

Weight = 20 kg * 10 m/s² = 200 N

Now, we can rearrange Hooke's Law to solve for the extension of the spring:

x = F / k

Substituting the values we have:

x = 200 N / 40 N/m = 5 meters

Therefore, the spring will stretch by 5 meters when a 20 kg weight is suspended from it.