Question

Девочки вылепили из пластилина бюст победителя школьной олимпиады по физике и поручили мальчикам отлить из золата его его точную копию но в 2 раз большей высоты. какую массу будет иметь отливка если на изготавление орасца пошло V= 100 см³ пластелина. плотность золота 19,3 г/см3

Answer 1

Высота точной копии из золота в 2 раза больше высоты бюста из пластилина. Значит, объём золотой копии в 2^3=8 раз больше пластилинового образца. При плотности золота 19,3 г/см^3, масса копии из золота составит 19,3*800=15440 г или 15,44 кг.
19 октября 2016 года сбербанк России продает золото по 3055 рублей за 1 г, значит, если золото покупать в сбербанке, то за него придется заплатить 3055*15440 = 47 169 200 рублей.

Answer 2

The question is about the mass of a gold replica of a clay bust that is twice as tall as the original. To answer this question, we need to use the concept of similar solids and the formula for density.

Similar solids are solids that have the same shape but different sizes. They have a constant ratio of corresponding linear dimensions, such as height, width, and length. This ratio is called the scale factor. For example, if two cubes have edge lengths of 2 cm and 4 cm, then the scale factor is 4/2 = 2.

The volume of a solid is proportional to the cube of its linear dimension. This means that if we multiply the linear dimension by the scale factor, we have to multiply the volume by the scale factor cubed. For example, if we double the edge length of a cube, we have to multiply the volume by 2^3 = 8.

Density is the ratio of mass to volume. It is a property of a material that does not depend on the size or shape of the object. The formula for density is:

$$\text{density} = \frac{\text{mass}}{\text{volume}}$$

To find the mass of an object, we can rearrange the formula as:

$$\text{mass} = \text{density} \times \text{volume}$$

Now, let us apply these concepts to the question. We are given that the clay bust has a volume of 100 cm^3 and the gold replica has a height that is twice as tall as the clay bust. We are also given that the density of gold is 19.3 g/cm^3.

To find the volume of the gold replica, we need to find the scale factor first. Since the height is doubled, the scale factor is 2. Then, we can multiply the volume of the clay bust by the scale factor cubed to get the volume of the gold replica:

$$\text{volume of gold replica} = \text{volume of clay bust} \times \text{scale factor}^3$$ $$\text{volume of gold replica} = 100 \times 2^3$$ $$\text{volume of gold replica} = 800 \text{ cm}^3$$

To find the mass of the gold replica, we can multiply the volume of the gold replica by the density of gold:

$$\text{mass of gold replica} = \text{volume of gold replica} \times \text{density of gold}$$ $$\text{mass of gold replica} = 800 \times 19.3$$ $$\text{mass of gold replica} = 15440 \text{ g}$$

Therefore, the mass of the gold replica is 15440 g. This is the answer to the question.

You can find more information about similar solids, density, and volume in the following web search results: , , . I hope this helps you understand the problem.