Question

Расстояние между двумя точечными зарядами q1=+8*10^-9 Кл q2=-6 *10^9 Кл равно 5 см. Какова напряженность поля в точке, находящейся на расстоянии 4 см от заряда q1 и 3 см от заряда q2помогите очень срочно !! заранее спасибо

Answer 1

E1= kq1 / ( r1)^2

E1= 9*10^9 *8*10^-9  /  ( 0,04)^2= 45000

E2= kq2 / (r2)^2

E2= 9*10^9 *6*10^-9 / (0,03) ^2= 60000

тк один заряд положит , а другой отрицат , то общее E= E1+ E2 и напрвлено в сторону к отрицательному

Е= 45000+ 60000= 105000 Н/кл

Answer 2

Calculation of Electric Field Intensity

To calculate the electric field intensity at a point located at a distance of 4 cm from the charge q1 and 3 cm from the charge q2, we can use the formula:

E = k * (q1 / r1^2) + k * (q2 / r2^2)

Where: - E is the electric field intensity - k is the electrostatic constant (approximately equal to 8.99 * 10^9 Nm^2/C^2) - q1 and q2 are the magnitudes of the charges - r1 and r2 are the distances from the charges to the point where the electric field is being calculated

In this case, q1 = 8 * 10^-9 C, q2 = -6 * 10^-9 C, r1 = 4 cm = 0.04 m, and r2 = 3 cm = 0.03 m.

Substituting these values into the formula, we get:

E = (8.99 * 10^9 Nm^2/C^2) * (8 * 10^-9 C / (0.04 m)^2) + (8.99 * 10^9 Nm^2/C^2) * (-6 * 10^-9 C / (0.03 m)^2)

Calculating this expression will give us the electric field intensity at the given point.

Please note that the charges are given in Coulombs (C) and the distances are given in meters (m).