Question

Тело брошено со скоростью 15 метров секунду под углом 30 градусов к горизонту. Найти высоту подъема

Answer 1

Hmax=V0^2*sin^2a/2*g=225*0,25/2*10=2,8 м

Answer 2

Calculation of the Maximum Height

To find the maximum height reached by the body, we can use the equations of motion. The initial velocity of the body is 15 m/s, and it is launched at an angle of 30 degrees to the horizontal.

The equation for the maximum height reached by a projectile launched at an angle is given by:

Hmax = (v0^2 * sin^2θ) / (2g)

Where: - Hmax is the maximum height reached - v0 is the initial velocity of the body - θ is the launch angle - g is the acceleration due to gravity (approximately 9.8 m/s^2)

Substituting the given values into the equation, we have:

Hmax = (15^2 * sin^2(30)) / (2 * 9.8)

Calculating this expression gives us the maximum height reached by the body.

Let's calculate it step by step:

1. Calculate the square of the initial velocity: - v0^2 = 15^2 = 225.

2. Calculate the sine of the launch angle: - sin(30) ≈ 0.5.

3. Substitute the values into the equation: - Hmax = (225 * 0.5^2) / (2 * 9.8).

4. Simplify the expression: - Hmax = (225 * 0.25) / 19.6.

5. Calculate the maximum height: - Hmax ≈ 2.86 meters.

Therefore, the maximum height reached by the body is approximately 2.86 meters.