Question

Определите давление в сосуде объемом 3·10-³ м³,который наполнен аргоном при температуре 0 C.Молярная масса аргона 0,04кг/моль,а масса аргона в сосуде 5,1·10-³кг.ПОМОГИТЕ ПЖ

Answer 1

Найди из уравнения Менделеева - Клапейрона:
PV=(m/M)RT

Answer 2

Calculation of Pressure in the Vessel

To calculate the pressure in the vessel, we can use the ideal gas law equation:

PV = nRT

Where: - P is the pressure - V is the volume of the vessel (given as 3·10^-3 m³) - n is the number of moles of the gas - R is the ideal gas constant (8.314 J/(mol·K)) - T is the temperature in Kelvin

First, let's convert the temperature from Celsius to Kelvin: 0°C + 273.15 = 273.15 K

Next, we need to calculate the number of moles of argon in the vessel. We can do this by dividing the mass of argon in the vessel by the molar mass of argon.

Given: - Molar mass of argon = 0.04 kg/mol - Mass of argon in the vessel = 5.1·10^-3 kg

Number of moles of argon = (Mass of argon in the vessel) / (Molar mass of argon)

Now we can substitute the values into the ideal gas law equation and solve for pressure:

PV = (Number of moles of argon) * R * T

Let's calculate the pressure using the given values:

Number of moles of argon = (5.1·10^-3 kg) / (0.04 kg/mol) Temperature (T) = 273.15 K Volume (V) = 3·10^-3 m³ Ideal gas constant (R) = 8.314 J/(mol·K)

Substituting the values into the equation:

Pressure (P) = ((5.1·10^-3 kg) / (0.04 kg/mol)) * (8.314 J/(mol·K)) * (273.15 K) / (3·10^-3 m³)

Calculating the result will give us the pressure in the vessel.