Question

мальчик массой 50 кг находится на тележке массой 50 кг движущейся слева направо по гладкой горизонтальной дороге со скоростью 1 м/с. Какими станут модуль и направление скорости тележки,если мальчик прыгнет с нее в направлении первоначальной скорости тележки со скоростью 3 м/с относительно дороге?

Answer 1

по зси

2*50*1=50*3+50*х

-50=50х

х=-1

получается модуль равен 1 а направление влево

 

Answer 2

Calculation of the Velocity of the Cart after the Boy Jumps Off

To calculate the velocity of the cart after the boy jumps off, we can use the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.

The momentum of an object is given by the product of its mass and velocity. Let's denote the mass of the boy as m1 (50 kg) and the mass of the cart as m2 (50 kg). The initial velocity of the cart is given as 1 m/s, and the velocity of the boy relative to the ground is given as 3 m/s.

Using the conservation of momentum equation, we can write:

m1 * V1 = (m1 + m2) * V

where V1 is the initial velocity of the boy relative to the ground, and V is the final velocity of the cart after the boy jumps off.

Substituting the given values:

(50 kg) * (3 m/s) = (50 kg + 50 kg) * V

Simplifying the equation:

150 kg*m/s = 100 kg * V

Dividing both sides by 100 kg:

V = 150 kg*m/s / 100 kg

V = 1.5 m/s

Therefore, the velocity of the cart after the boy jumps off will be 1.5 m/s in the same direction as the initial velocity of the cart (from left to right).