Question

Мотоциклист едет с ускорением 4м/с^2. какова сила тяги двигателя, если коэффициент трения 0,01 и масса системы 200 кг

Answer 1

Дано
a = 4
мю = 0.01
m = 200
найти
Fт


Анализ
Fр = ma
Fт - Fтр = m
Fт = мю * m * g
Fт = m (a + мю * g)

Answer 2

Calculation of the Engine Thrust Force

To calculate the force of engine thrust, we need to consider the acceleration of the motorcycle, the coefficient of friction, and the mass of the system.

Given: - Acceleration (a) = 4 m/s^2 - Coefficient of friction (μ) = 0.01 - Mass of the system (m) = 200 kg

The force of engine thrust can be calculated using the following equation:

Force of engine thrust = (mass of the system) * (acceleration) + (coefficient of friction) * (mass of the system) * (acceleration)

Substituting the given values into the equation:

Force of engine thrust = (200 kg) * (4 m/s^2) + (0.01) * (200 kg) * (4 m/s^2)

Calculating the result:

Force of engine thrust = 800 N + 8 N = 808 N

Therefore, the force of engine thrust is 808 Newtons (N).

Please note that the above calculation assumes that the force of engine thrust is the only force acting on the motorcycle. In reality, there may be other forces, such as air resistance, that can affect the motion of the motorcycle.