Question

Скоростной лифт массой 1.6 тонн поднимается в течение 30 секунд. Сила тока, потребляемого двигателем, равна 50 А, напряжение в сети 400 В. КПД двигателя 80%. Сколько электроэнергии затрачено на подъём? На какую высоту поднялся лифт? Напишите пожалуйста решение!!!

Answer 1

КПД=(А1/А2)*100*, А1=FS=mgh; A2=UIt=400*50*30=0,6 МДж на подъем затрачено. КПД=(mgh/A2)*100%; h=КПД *А2/(mg*100%)=0,8*6*10^5/1600*10=480*10^3/16*10^3=30 м

Answer 2

Calculation of Electrical Energy Consumed:

To calculate the electrical energy consumed by the lift, we can use the formula:

Electrical Energy (E) = Power (P) x Time (t)

The power consumed by the lift can be calculated using the formula:

Power (P) = Voltage (V) x Current (I)

Given: - Mass of the lift = 1.6 tons = 1600 kg - Time taken to lift = 30 seconds - Current consumed by the motor = 50 A - Voltage in the network = 400 V - Efficiency of the motor = 80%

First, let's calculate the power consumed by the motor:

Power (P) = Voltage (V) x Current (I) P = 400 V x 50 A

Now, let's calculate the electrical energy consumed:

Electrical Energy (E) = Power (P) x Time (t) E = P x t

To find the electrical energy consumed, we need to convert the power from watts to kilowatts, as the unit of electrical energy is kilowatt-hours (kWh).

1 kilowatt (kW) = 1000 watts (W)

Therefore, the power consumed by the motor in kilowatts is:

P (kW) = P (W) / 1000

Now, we can calculate the electrical energy consumed:

E (kWh) = P (kW) x t (hours)

Since the time given is in seconds, we need to convert it to hours:

1 hour = 3600 seconds

t (hours) = t (seconds) / 3600

Now, let's substitute the values and calculate the electrical energy consumed:

P (kW) = (400 V x 50 A) / 1000 t (hours) = 30 seconds / 3600

E (kWh) = P (kW) x t (hours)

Please note that the efficiency of the motor is not used in this calculation.

Let's calculate the electrical energy consumed.