Question

водяной пар массой 4 кг имеющий температуру 100 градусов цельсия конденсируется какое количество теплоты при этом выделяется

Answer 1

Q= - L*m, L=2260000 Дж/кг - уд. теплота парообразования воды при 100 градусах,
Q= - 2260000*4 = - 9040000 Дж = - 9040 кДж

Answer 2

Calculation of Heat Released when 4 kg of Steam Condenses

To calculate the amount of heat released when 4 kg of steam condenses, we need to use the specific heat capacity and latent heat of vaporization of water.

1. Specific Heat Capacity of Water: The specific heat capacity of water is the amount of heat energy required to raise the temperature of 1 kg of water by 1 degree Celsius. The specific heat capacity of water is approximately 4.18 J/g°C.

2. Latent Heat of Vaporization of Water: The latent heat of vaporization of water is the amount of heat energy required to change 1 kg of water from a liquid state to a gaseous state at its boiling point. The latent heat of vaporization of water is approximately 2,260 kJ/kg.

Now, let's calculate the amount of heat released when 4 kg of steam condenses.

First, we need to calculate the heat energy required to raise the temperature of 4 kg of water from 100°C to its boiling point:

Q1 = mass × specific heat capacity × temperature change = 4 kg × 4.18 J/g°C × (100°C - 100°C) = 0 J

Since the temperature change is 0°C, no heat energy is required to raise the temperature.

Next, we need to calculate the heat energy required to change 4 kg of water from a liquid state to a gaseous state:

Q2 = mass × latent heat of vaporization = 4 kg × 2,260 kJ/kg = 9,040 kJ

Therefore, when 4 kg of steam condenses, approximately 9,040 kJ of heat energy is released.

Please note that the values used in this calculation are approximate and may vary slightly depending on the specific conditions.