Question

№1.На паром,борта которого вертикальны,погрузили телегу со 100 кирпичами. Масса телеги с лошадью без кирпичей 549 кг. Размер кирпича 25 см х 12 см х 5 см.Площадь парома 25 м². На сколько увеличилась осадка парома? №2.К куску железа массой 11,7 г привязали кусок пробки весом 0,012 Н.При погружении этих связанных тел в воду вес их равен 0,064 Н. Определите плотность пробки. №3 Металлическая деталь весит в воздухе 44,5 Н,а при погружении в керосин - 40,5Н. Чему равно архимедова сила, действующая на деталь?

Answer 1

х -масса кирпича =0,25*0,12*0,05*q, где q-плотность кирпича ~1800 кг/м³

х=0,25*0,12*0,05*1800=2,7 кг масса кирпича

(549+100*х)/(1000*25)=0,02196+0,004х метров увеличилась осадка парома

0,02196+0,004х=0,02196+0,004*2,7=0,033 м

Answer 2

№1. На паром, борта которого вертикальны, погрузили телегу со 100 кирпичами. Масса телеги с лошадью без кирпичей 549 кг. Размер кирпича 25 см х 12 см х 5 см. Площадь парома 25 м². На сколько увеличилась осадка парома?

To calculate the increase in draft (osadka) of the ferry after loading the cart with bricks, we need to determine the total weight of the bricks and the weight of the ferry before and after loading.

The mass of the cart with the horse without bricks is given as 549 kg. We need to calculate the mass of the bricks.

To find the mass of the bricks, we need to know the density of the bricks. Unfortunately, the density of the bricks is not provided in the question. Therefore, we cannot calculate the mass of the bricks and subsequently the increase in draft of the ferry.

Please provide the density of the bricks or any additional information required to calculate the increase in draft of the ferry.

№2. К куску железа массой 11,7 г привязали кусок пробки весом 0,012 Н. При погружении этих связанных тел в воду вес их равен 0,064 Н. Определите плотность пробки.

To determine the density of the cork, we can use Archimedes' principle, which states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

In this case, the weight of the iron piece is given as 11.7 g and the weight of the combined iron and cork when submerged in water is 0.064 N.

First, let's convert the weight of the iron piece from grams to Newtons: 11.7 g = 11.7 * 9.8 m/s² = 114.66 N

Next, we can calculate the weight of the cork alone by subtracting the weight of the iron piece from the total weight when submerged in water: Weight of cork = Total weight - Weight of iron piece Weight of cork = 0.064 N - 114.66 N = -114.596 N

Since the weight of the cork is negative, it means that the buoyant force acting on the cork is greater than its weight. This indicates that the cork is less dense than water.

To calculate the density of the cork, we can use the formula: Density = Mass / Volume

Since we have the weight of the cork, we can use the formula: Density = Weight / (Acceleration due to gravity * Volume)

Let's calculate the volume of the cork: Volume = Weight of cork / (Acceleration due to gravity) Volume = -114.596 N / (9.8 m/s²) = -11.69 kg

Since the volume cannot be negative, it seems there might be an error in the given information or calculations. Please double-check the values provided or provide additional information if available.

№3. Металлическая деталь весит в воздухе 44,5 Н, а при погружении в керосин - 40,5 Н. Чему равно архимедова сила, действующая на деталь?

To determine the buoyant force (Archimedes' force) acting on the metal object, we can use Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.

In this case, the weight of the metal object in air is given as 44.5 N, and the weight of the metal object when submerged in kerosene is 40.5 N.

The buoyant force acting on the metal object is equal to the weight of the kerosene displaced by the object. Therefore, we can calculate the buoyant force by subtracting the weight of the metal object in kerosene from its weight in air:

Buoyant force = Weight in air - Weight in kerosene Buoyant force = 44.5 N - 40.5 N = 4 N

Therefore, the Archimedes' force acting on the metal object is 4 N.