Question

Индуктивность контура 0.05Гн частота волн 1000Гц .Найдите емкость конденсатора

Answer 1

Ёмкость контура С с резонансной частотой f0 и индуктивностью L определяется исходя из формулы для расчёта резонансной частоты как С=1/(4*π²*L*f0²)=1/(4*3,14²*0,05*10⁶)=5,071*10-⁷ Ф.
Ответ: 5,071*10-⁷ Ф.

Answer 2

Inductance and Capacitance in an Electrical Circuit

To find the capacitance of a capacitor in a circuit with an inductance of 0.05 H and a frequency of 1000 Hz, we can use the formula that relates the inductance, capacitance, and frequency in an electrical circuit.

The formula is given by:

1 / (2 * π * √(L * C)) = f

Where: - L is the inductance of the circuit (0.05 H in this case) - C is the capacitance of the capacitor (to be determined) - f is the frequency of the circuit (1000 Hz in this case) - π is a mathematical constant approximately equal to 3.14159

To find the capacitance, we can rearrange the formula as follows:

C = 1 / (4 * π^2 * L * f^2)

Now, let's substitute the given values into the formula and calculate the capacitance.

C = 1 / (4 * π^2 * 0.05 * 1000^2)

Calculating this expression gives us the value of the capacitance.

Please note that the above formula assumes an ideal circuit without any resistance or other components. In practical circuits, other factors may need to be considered.

Let's calculate the capacitance using the formula.