Question

Под действием силы 320 Н пружина амортизатора сжалась на 9 мм.На сколько миллиметров сожмётся пружина при нагрузки 1,60 кН?

Answer 1

F 1 = 320 H
F 2 = 1600 H
l1 = 9 мм = 9 * 10^-3м
 l2 - ?

зависимость между силой упругости и деформации пружины прямо пропорциональна, т.е :
F1/l1 = F2/l2 => l2 = l1 * F2/ F1
l2 = 9*10^-3м * 1600 H/ 320 H = 45*10^-3м = 45 мм

Answer 2

Calculation of Spring Compression

To calculate the compression of a spring under a given force, we can use Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement of the spring from its equilibrium position.

Hooke's Law can be expressed as:

F = k * x

Where: - F is the force applied to the spring - k is the spring constant (a measure of the stiffness of the spring) - x is the displacement of the spring from its equilibrium position

In this case, we are given that the force applied to the spring is 320 N and the spring compresses by 9 mm. We need to find the compression of the spring when a force of 1.60 kN (1600 N) is applied.

To find the spring constant, we can rearrange Hooke's Law:

k = F / x

Let's calculate the spring constant first:

k = 320 N / 9 mm

Converting millimeters to meters:

k = 320 N / 0.009 m

k = 35,556.0 N/m

Now, we can use the spring constant to find the compression of the spring when a force of 1.60 kN (1600 N) is applied:

F = k * x

1600 N = 35,556.0 N/m * x

Solving for x:

x = 1600 N / 35,556.0 N/m

x ≈ 0.045 m

Converting meters to millimeters:

x ≈ 45 mm

Therefore, the spring will compress by approximately 45 mm when a force of 1.60 kN is applied.

Please note that the calculations provided are based on the information given and the assumption that the spring follows Hooke's Law.