Question

Камень весит в воздухе 50 Н. а при полном погружении в воду 20 Н. Определите вес вытесненной воды,объем камня и его плотность. Ребят много этих баллов даю,пожалуйста помогите,вообще не могу понять как сделать)) Заранее спасибо)) бред не писать))

Answer 1

Начнем с самого простого, веса вытесненной воды:
Камень весил в воздухе 50Н , а в воде 20Н, значит разница 50Н-20Н=30Н, значит сила Архимеда на камень со стороны выды равна 30Н и вес вытесненной части воды равен 30Н.
Найдем объем:
Сила Архимеда = плотность жидкости (для воды 1000 кг/m^3) * ускорение свободного падения (10Н/кг) * обьем погруженной части тела ( в нашем случае весь камень) F=p*g*V. Значит объем = 30/(1000*10)=0,003m^3
Плотность камня:
Плотность = масса/объем p=m/V
масса= вес/ускорение свободного падения m=P/g
m=50/10=5кг
p=5/0,003=1667кг/m^3
Ответ: Вес вытесненной воды 30Н
Объем камня 0,003м^3
Его плотность :1667кг/m^3

Answer 2

1) P=F1-F2=30H 2)P=pgV.V=P/pg=0.003 м3(3 дм3) 3)m=F1/g=(5 кг) p=m/v= 1666.7(кг/м3) Ответ 1) 30Н 2)3 дм3 3) 1666.7кг/м3

Answer 3

Problem Analysis

To solve this problem, we need to determine the weight of the displaced water, the volume of the stone, and its density. We are given that the weight of the stone in the air is 50 N and its weight when fully submerged in water is 20 N.

Weight of the Displaced Water

When an object is submerged in a fluid, it displaces an amount of fluid equal to its own volume. According to Archimedes' principle, the weight of the displaced fluid is equal to the buoyant force acting on the object. In this case, the weight of the displaced water is equal to the difference between the weight of the stone in the air and its weight when submerged in water.

The weight of the displaced water can be calculated using the formula:

Weight of the displaced water = Weight of the stone in the air - Weight of the stone in water

Volume of the Stone

The volume of the stone is equal to the volume of the water it displaces. We can calculate the volume of the stone using the formula:

Volume of the stone = Volume of the displaced water

Density of the Stone

The density of an object is defined as its mass per unit volume. In this case, we can calculate the density of the stone using the formula:

Density of the stone = Mass of the stone / Volume of the stone

Since we are not given the mass of the stone directly, we will need to use the weight of the stone and the acceleration due to gravity to calculate the mass. The weight of an object can be calculated using the formula:

Weight = Mass x Acceleration due to gravity

By rearranging the formula, we can solve for the mass:

Mass = Weight / Acceleration due to gravity

Once we have the mass of the stone, we can use it to calculate the density.

Calculation

Let's perform the calculations using the given information.

1. Weight of the displaced water: - Weight of the stone in the air = 50 N - Weight of the stone in water = 20 N - Weight of the displaced water = 50 N - 20 N = 30 N

2. Volume of the stone: - Volume of the displaced water = Volume of the stone

3. Density of the stone: - Mass of the stone = Weight of the stone / Acceleration due to gravity - Density of the stone = Mass of the stone / Volume of the stone

Answer

Based on the calculations, the weight of the displaced water is 30 N. The volume of the stone is equal to the volume of the displaced water. The density of the stone can be calculated using the mass of the stone and the volume of the stone.

Please note that without additional information, we cannot provide the exact numerical values for the volume and density of the stone. However, you can use the formulas and the given information to calculate these values once you have the mass of the stone.

I hope this helps! Let me know if you have any further questions.