Question

найти напряжонность поля в точке, где помещен заряд 2нКл. на данный заряд действует сила 0,4 мкН. Помогите пожалуйста!

Answer 1

E=F/q=0.4*10^(-6)/2*10^(-9)=200 Н/Кл 

Answer 2

Calculating the electric field strength at a point due to a charge

The question asks us to find the electric field strength E at a point where a charge of 2nC is located, and this charge experiences a force of 0.4mN.

To solve this, we can use the formula:

`F = qE`

Where: - F is the force in newtons (N) - q is the charge in coulombs (C) - E is the electric field strength in newtons per coulomb (N/C)

Given: - Charge (q) = 2nC - Force (F) = 0.4mN

Substituting into the formula:

`0.4mN = (2nC)E` `E = 0.4mN / 2nC` E = 0.2N/C

Therefore, the electric field strength at the point where the 2nC charge is located, due to that charge, is 0.2N/C.