Question

Материальная точка за 1 мин совершила 300 колебаний. определите период колебаний и частоту

Answer 1

Т = t /N, где
Т - период
t - время
N - число колебаний
Т = 60 с / 300 = 0, 2 с
Y(частота) = 1/Т
Y =1 / 0,2 = 5 Гц

Answer 2

Calculation of Period and Frequency

To determine the period and frequency of the oscillations, we need to use the formula:

Period (T) = 1 / Frequency (f)

Given that the material point completes 300 oscillations in 1 minute, we can calculate the period and frequency as follows:

Period (T) = 1 minute / 300 oscillations

To convert the period to seconds, we need to know the duration of 1 minute in seconds. According to the search results, 1 minute is equal to 60 seconds Therefore, the period can be calculated as:

Period (T) = 60 seconds / 300 oscillations

Simplifying the equation:

Period (T) = 0.2 seconds

Now, we can calculate the frequency using the formula mentioned earlier:

Frequency (f) = 1 / Period (T)

Substituting the value of the period:

Frequency (f) = 1 / 0.2 seconds

Simplifying the equation:

Frequency (f) = 5 Hz

Therefore, the period of the oscillations is 0.2 seconds, and the frequency is 5 Hz.