Question

Два проводника сопротивлением 10Ом и 23Ом включены в круг с напряжением 100В. Какое количество тeплоты выделится за 1с. в каждом проводнике, если их соединить последовательно?

Answer 1

Суммарное сопротивление при последовательном соединении равно R=10+23=33 Ом. Сила тока в цепи I=100/R=100/33=3,03 А. Количество теплоты за время t равно Q=I²*R*t=3,03²*33*1=302,97 Дж.

Ответ: 302,97 Дж.

Answer 2

Calculation of Heat Generated in Each Resistor

To calculate the amount of heat generated in each resistor when they are connected in series, we can use the formula:

Q = I^2 * R * t

Where: - Q is the heat generated in Joules (J) - I is the current flowing through the resistor in Amperes (A) - R is the resistance of the resistor in Ohms (Ω) - t is the time in seconds (s)

In this case, we have two resistors with resistances of 10Ω and 23Ω, respectively, and a voltage of 100V applied across the circuit. Since the resistors are connected in series, the current flowing through both resistors will be the same.

To find the current, we can use Ohm's Law:

I = V / R

Where: - V is the voltage applied across the circuit in Volts (V)

Let's calculate the current first:

I = 100V / (10Ω + 23Ω)

Calculating the sum of the resistances:

I = 100V / 33Ω

I ≈ 3.03A

Now that we have the current, we can calculate the heat generated in each resistor for a duration of 1 second:

For the resistor with a resistance of 10Ω:

Q1 = (3.03A)^2 * 10Ω * 1s

For the resistor with a resistance of 23Ω:

Q2 = (3.03A)^2 * 23Ω * 1s

Let's calculate the values:

Q1 ≈ 92.43J

Q2 ≈ 212.07J

Therefore, approximately 92.43 Joules of heat will be generated in the resistor with a resistance of 10Ω, and approximately 212.07 Joules of heat will be generated in the resistor with a resistance of 23Ω, when they are connected in series and a voltage of 100V is applied across the circuit for 1 second.