Question

В сосуде под поршнем при 1000 градусах находится 2 грамма пара и такое же количесвтво воды. Сколько испарится воды, если увеличить объем сосуда в три раза при 100 градусах?

Answer 1

Вроде так, только я не уверена , что правильно, но у меня такая же задача в книге и ответ такой же получился)

Answer 2

Calculation of Water Evaporation

To calculate the amount of water that will evaporate when the volume of the vessel is increased three times at a temperature of 100 degrees Celsius, we need to consider the initial conditions and the change in volume.

Given: - Temperature: 1000 degrees Celsius - Amount of steam: 2 grams - Amount of water: 2 grams

To find the amount of water that will evaporate, we can use the ideal gas law, which states that the pressure, volume, and temperature of a gas are related by the equation PV = nRT, where: - P is the pressure - V is the volume - n is the number of moles of gas - R is the ideal gas constant - T is the temperature in Kelvin

Since we are dealing with water vapor, we can assume it behaves ideally. The molar mass of water is approximately 18 g/mol.

To calculate the initial number of moles of water vapor, we can use the equation n = m/M, where: - n is the number of moles - m is the mass of the substance - M is the molar mass of the substance

Using this equation, we can find the initial number of moles of water vapor: n_initial = m_initial / M_water n_initial = 2 g / 18 g/mol n_initial ≈ 0.111 moles

Since the amount of water is the same as the amount of steam, the initial number of moles of water is also 0.111 moles.

Now, let's consider the change in volume. The volume of the vessel is increased three times. This means the final volume will be three times the initial volume.

To find the final number of moles of water vapor, we can use the equation n_final = n_initial * (V_final / V_initial), where: - n_final is the final number of moles - n_initial is the initial number of moles - V_final is the final volume - V_initial is the initial volume

Since the volume is increased three times, we have: V_final = 3 * V_initial

Substituting the values into the equation, we get: n_final = 0.111 moles * (3 / 1) n_final = 0.333 moles

To find the mass of water that will evaporate, we can use the equation m_final = n_final * M_water, where: - m_final is the final mass - n_final is the final number of moles - M_water is the molar mass of water

Substituting the values into the equation, we get: m_final = 0.333 moles * 18 g/mol m_final ≈ 6 grams

Therefore, when the volume of the vessel is increased three times at a temperature of 100 degrees Celsius, approximately 6 grams of water will evaporate.

Please note that this calculation assumes ideal gas behavior and does not take into account factors such as pressure changes or non-ideal conditions.