Question

Найти период колебаний в колебательном контуре , состоящий из конденсатора с емкостью 8 пф и катушки индуктивности 2гн. желательно фото решения!!!

Answer 1

С=8пф=8*10^-12 Ф
L=2Гн
T=2π[tex]\sqrt{LC} } [/text]=6,28*4*10^-6=25,12*10^-4=0,002512 c

Answer 2

Calculation of the Period of Oscillation in an LC Circuit

To find the period of oscillation in a simple LC circuit, we need to use the formula:

T = 2π√(L*C)

where T is the period of oscillation, L is the inductance of the coil, and C is the capacitance of the capacitor.

In this case, we have an LC circuit with a capacitor of 8 pF and an inductance of 2 H.

Substituting the given values into the formula, we get:

T = 2π√(2 * 8 * 10^(-12))

To calculate the period, we need to evaluate this expression.

Let's perform the calculation:

T = 2π√(2 * 8 * 10^(-12))

T ≈ 2π√(1.6 * 10^(-11))

T ≈ 2π * 1.2649110640673518 * 10^(-6)

T ≈ 7.957747154594767 * 10^(-6)

Therefore, the period of oscillation in the given LC circuit is approximately 7.96 microseconds.

Please note that the above calculation is based on the given values of the capacitance and inductance.